-\parallel\mathbf{x}\parallel > 0
-\parallel k\mathbf{x}\parallel = k \parallel\mathbf{x}\parallel
-\parallel \mathbf{x+y}\parallel \le \parallel\mathbf{x}\parallel+ \parallel\mathbf{y}\parallel
It can simply be verified that the Euclidean length is a vector norm:
\parallel\mathbf{x}\parallel = \sqrt{x_1^2 + x_2^2 + \cdots + x_n^x}
There is an entire class of norms called the l_p-norms:
\parallel\mathbf{x}\parallel_p = (x_1^p + x_2^p + \cdots + x_n^p)^{\frac{1}{p}},
of which the Euclidean length or Euclidean norm is a member for p=2.
A very interesting ( and surprising ) norm is the l_\infty-norm:
\parallel\mathbf{x}\parallel_{\infty} = \max{(|x_1|, |x_2|, \cdots, |x_n|)},
this behavior can be explained from the fact that the higher the p, the more l_p is dominated by the element of the largest magnitude.
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