Contined fractions (2a)

I found a better way to present the table which shows the algorithm for calculating continued fractions:

$k$	$a_k$	$p_k$	$q_k$	$C_k$
$-1$		$0$	1
$0$		$1$	$0$
$k$	$a_k$	$a_k \cdot p_{k-1} + p_{k-2}$	$a_k \cdot q_{k-1} + q_{k-2}$	$\frac{p_k}{q_k}$

The table consists of $m+2$ rows. The value of the FCF is $\frac{p_m}{q_m}$.

To be continued.

See also:
- Continued fractions (1)
- Continued fractions (2)